## Introduction

If you have studied or have done some wood design, you certainly have came across the “beam stability factor”.

It looks something like this ((NDS Equation 3.3–6):

Now, I am not going to go into details about all the variables; I mainly just wanted to talk about the final C_{L} factor.

As you already know, once you obtained F_{bE} and F_{b}^{*}, calculating C_{L} is merely plug-and-chug. **It is very straightforward yet tedious…**

I can’t remember the number of times that I accidentally plugged in the wrong numbers or made a silly mistake when punching the numbers into a calculator. The result, as you guessed it, is usually not pretty (depending on how early I find out about the mistake).

So I came up with a simpler way to avoid doing all of these tedious “plug-and-chug”.

**Introducing – Tabulated Table For Beam Stability Factor:**

**Wood CL Tabulation 291.59 KB**

This table not only helped me avoid making arithmetical errors, it also saved me quite some times during the SE exam (which you know, every second counts!) And before I knew it, life was good again (ok that might be exaggerating a little but you get the idea).

## How To Use The Tabulated Table for Beam Stability Factor

Since C_{L} only depends on [F_{bE} / F_{b}^{*}], I figured if I have a table that lists out all of the possible [F_{bE} / F_{b}^{*}] and its corresponding C_{L}, I’ll never have to use a calculator to “plug-and-chug” again.

**So the way to use it is very simple:**

**First, determine the [F**_{bE}/ F_{b}^{*}] ratio up to 2 or 3 decimal points.**Then, find your C**_{L}.

#### Example 5.3 (SERM)

Let’s test this out using Example 5.3 of the Structural Engineering Reference Manual (SERM).

- [F
_{bE}/ F_{b}^{*}] = 2.83 from the example. - 2.83 falls in between 2.54 and 3.42; therefore, use C
_{L}= 0.97.

And we are done! (Although the actual C_{L} is 0.974, a difference of 0.004 will not make much difference to your design 99% of the time.)

#### Example 5.4 (SERM)

Let us do another one using Example 5.4.

- [F
_{bE}/ F_{b}^{*}] = 1.06. - For this part, we first match 1.0 to the first column then we find 0.06 in the top row. The result is C
_{L}= 0.840. Done!

Imagine doing this simple two-step process using the table versus hand calculating the following using a non-graphical calculator…

See the difference? I hope so because it sure helped me quite a bit.

## Next: Tabulated Table for Column Stability Factor

Similar to the Beam Stability Factor, Column Stability Factor also requires you do the same thing – tedious plug-n-chug (NDS Equation 3.7-1):

In this case, besides [F_{cE} / F_{c}^{*}], there is one more variable, c, which can be 0.8, 0.85, or 0.9 depending on the type of lumber.

No problem, I’ll just create 3 more tables.

If you find the table for Beam Stability Factor useful,** click the button below to gain access to the “Tabulated Table for Column Stability Factor” as well as ALL of the other helpful resources** that I only share with our subscribers.

**Click Here to get the Free Resources**

Come back here to see the example below once you get a chance to download the table and to visit our “subscriber-only area.”

#### Example 5.7 (SERM)

We’ll test this out using again, the example from SERM. From example 5.7:

- [F
_{cE}/ F_{c}^{*}] = 0.333 and c = 0.8. - 0.33 corresponds to C
_{P}= 0.304… and done.

Again, by using the table, you avoided having to do this during the exam:

## Thoughts?

That’s it for now. Do you find this helpful? Let me know in the comments below.

Thank you for reading and good luck studying!